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+Hi, I am solving a problem on leetcode: https://leetcode.com/problems/roman-to-integer/
+And my code is failing the test:.. The code is: `int romanToInt(char * s){
+    int stringSize; 
+    stringSize = strlen(s);
+    int ans, counter;
+    int pos_I=0, pos_V=0, pos_X=0, pos_L=0, pos_C=0, pos_D=0, pos_M=0; 
+    ans = 0;
+    counter = 0;
+    for(counter=0; counter<stringSize; counter++)
+    {
+        if (s[counter] == 'I')
+        {
+            //store the position of I
+            pos_I = counter;
+            ans = ans + 1; 
+             
+        }
+        else if (s[counter] == 'V')
+        {
+            pos_V = counter;
+            ans = ans + 5; 
+            if (counter >=1 )
+            {
+            if ((s[counter-1] == 'I') && counter >= 1)
+            {
+                ans = ans - 1; 
+            } }
+        }
+        else if (s[counter] == 'X')
+        {
+            pos_X = counter;
+            ans = ans + 10; 
+            if (counter >=1 )
+            {
+            if ((s[counter-1] == 'I') && (counter >=1))
+            {
+                ans = ans - 1; 
+            } }            
+        }
+        else if (s[counter] == 'L')
+        {
+            pos_L = counter;
+            ans = ans + 50; 
+            if (counter >= 1)
+            {
+            if ((s[counter-1] == 'X') && (counter >= 1))
+            {
+                ans = ans - 10; 
+            } }
+        }
+        else if (s[counter] == 'C')
+        {
+            pos_C = counter;
+            ans = ans + 100;
+            if (counter >= 1)
+            { 
+            if ((s[counter-1] == 'X') && (counter>=1))
+            {
+                ans = ans - 10; 
+            }}            
+        }`
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