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#include <stdio.h> |
#include <stdio.h> |
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#include "utils.h" |
#include "utils.h" |
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#include <stdlib.h> |
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/*
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/*
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A unit fraction contains 1 in the numerator. The decimal representation of the unit fractions with denominators 2 to 10 are given: |
Euler discovered the remarkable quadratic formula: |
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1/2 = 0.5 |
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1/3 = 0.(3) |
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1/4 = 0.25 |
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1/5 = 0.2 |
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1/6 = 0.1(6) |
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1/7 = 0.(142857) |
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1/8 = 0.125 |
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1/9 = 0.(1) |
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1/10 = 0.1 |
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Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle. It can be seen that 1/7 has a 6-digit recurring cycle. |
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Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part. |
It turns out that the formula will produce 40 primes for the consecutive integer values . However, when is divisible by 41, and certainly when is clearly divisible by 41. |
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https://projecteuler.net/problem=26
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The incredible formula was discovered, which produces 80 primes for the consecutive values . The product of the coefficients, −79 and 1601, is −126479. |
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*/ |
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boolean isPrime(int*primeList,int primeListSize,int numb) { |
Considering quadratics of the form: |
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for (int i=0;i<primeListSize;i++) { |
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if (numb==primeList[i]) { |
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return true; |
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} |
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} |
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return false; |
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} |
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int*getFactors(int numb) { |
, where and
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int*factorList=malloc(sizeof(int)*1); |
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int factorListSize=2; |
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factorList[0]=1; |
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factorList[1]=numb; |
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int max=numb; |
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for (int i=2;i<max;i++) { |
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if (numb%i==0) { |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=i; |
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if (numb/i!=i) { |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=numb/i; |
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max=numb/i; |
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} |
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} |
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} |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=0; |
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return factorList; |
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} |
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boolean isFactor(int*factorList,int numb) { |
where is the modulus/absolute value of
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int counter=0; |
e.g. and
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while (factorList[counter]!=0) { |
Find the product of the coefficients, and , for the quadratic expression that produces the maximum number of primes for consecutive values of , starting with . |
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if (numb==factorList[counter]) { |
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return true; |
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} |
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counter++; |
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} |
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return false; |
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} |
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const int TARGET_REPEATS_REQUIRED=100000; |
https://projecteuler.net/problem=27
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*/ |
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int main(int argc,char**argv) { |
int main(int argc,char**argv) { |
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int divider=0; |
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int divisor=2; |
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int sequence[TARGET_REPEATS_REQUIRED]; //Let's assume for the sake of sanity that 100000 repeating digits is enough. I sure hope so.
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int sequenceLength=0; |
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int sequenceRepeat=0; |
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int sequenceMarker=-1; |
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int longestCycleLength=0; |
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int longestCycleDivisor=0; |
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int longestSequence[TARGET_REPEATS_REQUIRED/10]; |
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int*primeList=malloc(sizeof(int)*0); |
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int primeListSize=0; |
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FILE*f = fopen("archives/primegenerator/primes","r"); |
FILE*f = fopen("archives/primegenerator/primes","r"); |
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while (fgetc(f)!='{'); |
int startMarker=0; |
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while (true) { |
while (fgetc(f)!='{') { |
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char c; |
startMarker++; |
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int digit=0; |
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while ((c=fgetc(f))!=',') { |
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digit*=10; |
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digit+=c-'0'; |
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}
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if (digit>=1000) { |
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break; |
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} else { |
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primeList=realloc(primeList,sizeof(int)*++primeListSize); |
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primeList[primeListSize-1]=digit; |
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} |
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} |
} |
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fseek(f,startMarker,SEEK_SET); |
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int n=0; |
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while (true) { |
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for (int a=1;a<1000;a++) { |
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for (int b=1;b<=1000;b++) { |
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while (divisor<1000) { |
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divider=10; //We always start with 10.
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sequenceLength=0; |
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sequenceRepeat=0; |
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for (int i=0;i<sequenceLength;i++) { |
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sequence[i]=0; |
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} |
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sequenceMarker=-1; |
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while (sequenceLength<TARGET_REPEATS_REQUIRED) { |
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int result=divider/divisor; |
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//printf("%d/%d = %d\n",divider,divisor,result);
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divider=divider%divisor; |
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sequence[sequenceLength++]=result; |
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divider*=10; |
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if (divider==0) { |
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//We're solved.
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break; |
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} |
} |
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} |
} |
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/*printf("%d:",divisor);
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for (int i=0;i<sequenceLength;i++) { |
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printf("%d",sequence[i]); |
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} |
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printf("\n");*/ |
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//We need to look at all combinations of possible repeating sequences.
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//Starting from iteration loop of length 1, and an offset incrementing by 1, see if anything remains the same.
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//Then do this for iteration loop of length 2, offset incrementing by 1, etc.
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//Find it repeating at least 20 times to assume it repeats infinitely.
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boolean isP = isPrime(primeList,primeListSize,divisor); |
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int*factors = getFactors(divisor-1); |
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int counter=0; |
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/*if (isP) {
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printf("Possible length factors of (%d-1):",divisor); |
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while (factors[counter]!=0) { |
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printf("%d,",factors[counter]); |
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counter++; |
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} |
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printf("\n"); |
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}*/ |
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boolean matched=false; |
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if (sequenceLength==TARGET_REPEATS_REQUIRED) { |
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for (int checkLength=0;checkLength<TARGET_REPEATS_REQUIRED/10;checkLength++) { |
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if (isP&&!isFactor(factors,checkLength+1)) {continue;} |
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for (int offset=0;offset<sequenceLength+1-checkLength;offset++) { |
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int sequenceStore[checkLength+1]; |
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int requiredCheckAmt=TARGET_REPEATS_REQUIRED/10-2; |
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for (int i=0;i<checkLength+1;i++) { |
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sequenceStore[i]=sequence[i+offset]; |
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/*printf("%d:",divisor);
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for (int i=0;i<checkLength+1;i++) { |
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printf("%d",sequenceStore[i]); |
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} |
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0010030090270812437311935807422266800401203610832497492477432296890672016048144433299899699097291875626880641925777331995987963891675025075225677031093279839518555667 |
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0010030090270812437311935807422266800401203610832497492477432296890672016048144433299899699097291875626880641925777331995987963891675025075225677031093279839518555667 |
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printf("\n");*/ |
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} |
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//Now if this repeating sequence can be found requiredCheckAmt times, we're golden.
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boolean allMatching=true; |
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int currentOffset=0; |
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int found=0; |
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while (requiredCheckAmt>0&&found<20) { |
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for (int i=0;i<checkLength+1;i++) { |
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//printf(" Compare %d to %d\n",sequence[offset+currentOffset+checkLength+1+i],sequenceStore[i]);
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if (sequence[offset+currentOffset+checkLength+1+i]!=sequenceStore[i]) { |
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allMatching=false; |
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goto check; |
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} |
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} |
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requiredCheckAmt--; |
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currentOffset+=checkLength+1; |
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found++; |
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//printf("Found a repeat.");
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} |
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check: |
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if (allMatching) { |
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printf("Longest repeating sequence for %d is of length %d: ",divisor,checkLength+1); |
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for (int i=0;i<checkLength+1;i++) { |
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printf("%d",sequenceStore[i]); |
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} |
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printf("\n"); |
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if (longestCycleLength<checkLength+1) { |
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longestCycleLength=checkLength+1; |
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longestCycleDivisor=divisor; |
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for (int i=0;i<longestCycleLength;i++) { |
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longestSequence[i]=sequenceStore[i]; |
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} |
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} |
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matched=true; |
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goto next; |
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} |
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} |
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} |
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} else { |
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matched=true; |
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printf("Longest repeating sequence for %d is of length 0.\n",divisor); |
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} |
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next: |
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free(factors); |
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if (!matched) { |
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printf("Not enough data to calculate longest repeating sequence for %d!\nQuitting...\n",divisor); |
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return 1; |
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} |
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divisor++; |
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} |
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printf("\n\nThe largest repeating sequence length is from %d with %d in length.",longestCycleDivisor,longestCycleLength); |
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printf("\n\tSequence: "); |
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for (int i=0;i<longestCycleLength;i++) { |
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printf("%d",longestSequence[i]); |
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} |
} |
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printf("\n"); |
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return 0; |
return 0; |
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} |
} |
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