Co-authored-by: sigonasr2 <sigonasr2@gmail.com>
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archives/6/current
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archives/6/current
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26
archives/6/src/main.c
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26
archives/6/src/main.c
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#include <stdio.h>
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#include "utils.h"
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/*
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The sum of the squares of the first ten natural numbers is,
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The square of the sum of the first ten natural numbers is,
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Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is .
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Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
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https://projecteuler.net/problem=6
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*/
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int main(int argc,char**argv) {
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int sumOfSquares=0,squareOfSum=0;
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for (int i=0;i<=100;i++) {
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sumOfSquares+=i*i;
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}
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for (int i=0;i<=100;i++) {
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squareOfSum+=i;
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}
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squareOfSum*=squareOfSum;
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printf("%d - %d = %d",squareOfSum,sumOfSquares,squareOfSum-sumOfSquares);
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return 0;
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}
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archives/6/src/utils.h
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archives/6/src/utils.h
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#define true 1
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#define false 0
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#define boolean char
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struct String{
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int length;
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char*str;
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};
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src/main.c
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src/main.c
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#include "utils.h"
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#include "utils.h"
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/*
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/*
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2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
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The sum of the squares of the first ten natural numbers is,
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What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
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The square of the sum of the first ten natural numbers is,
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https://projecteuler.net/problem=5
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Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is .
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Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
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https://projecteuler.net/problem=6
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*/
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*/
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int main(int argc,char**argv) {
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int main(int argc,char**argv) {
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int numb=1;
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int sumOfSquares=0,squareOfSum=0;
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while (true) {
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for (int i=0;i<=100;i++) {
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boolean isDivisible=true;
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sumOfSquares+=i*i;
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for (int i=1;i<=20;i++) {
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if (numb%i!=0) {
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isDivisible=false;
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break;
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}
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}
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if (isDivisible) {
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printf("%d is divisible!",numb);
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break;
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} else {
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numb++;
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}
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}
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}
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for (int i=0;i<=100;i++) {
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squareOfSum+=i;
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}
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squareOfSum*=squareOfSum;
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printf("%d - %d = %d",squareOfSum,sumOfSquares,squareOfSum-sumOfSquares);
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return 0;
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return 0;
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}
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}
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