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#include <stdio.h> |
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#include "utils.h" |
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#include <math.h> |
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/*
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Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits: |
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1634 = 14 + 64 + 34 + 44 |
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8208 = 84 + 24 + 04 + 84 |
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9474 = 94 + 44 + 74 + 44 |
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As 1 = 14 is not a sum it is not included. |
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The sum of these numbers is 1634 + 8208 + 9474 = 19316. |
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Find the sum of all the numbers that can be written as the sum of fifth powers of their digits. |
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https://projecteuler.net/problem=30
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*/ |
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int main(int argc,char**argv) { |
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int counter=0; |
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int currentDigit=10; |
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long digitSum=0; |
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while (counter<10000000) { |
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int tempNumb=currentDigit; |
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digitSum=0; |
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long val=0; |
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while (tempNumb>0) { |
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int digit=tempNumb%10; |
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tempNumb/=10; |
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val=(long)pow(digit,5); |
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digitSum+=val; |
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if (digitSum>currentDigit) { |
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goto next; |
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} |
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} |
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if (digitSum==currentDigit) { |
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printf("%d has a digit sum that equals its number!\n",currentDigit); |
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} |
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next: |
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currentDigit++; |
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counter++; |
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} |
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return 0; |
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} |
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#include "utils.h" |
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#include <stdio.h> |
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#include <stdlib.h> |
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struct String mult(struct String numb1, struct String numb2) { |
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struct String n1 = numb1; |
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struct String n2 = numb2; |
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byte carryover = 0; |
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if (numb2.length>numb1.length) { |
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n1=numb2; |
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n2=numb1; |
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} |
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int addends[n2.length][n1.length+1]; |
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for (int i=0;i<n2.length;i++) { |
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for (int j=0;j<n1.length+1;j++) { |
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addends[i][j]=0; |
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} |
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} |
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for (int i=n2.length-1;i>=0;i--) { |
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carryover=0; |
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for (int j=n1.length-1;j>=0;j--) { |
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int mult = (n1.str[j]-'0')*(n2.str[i]-'0')+((carryover!=0)?carryover:0); |
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//printf(" %d/%d\n",mult,carryover);
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carryover=0; |
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if (mult>=10) { |
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carryover=mult/10; |
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mult=mult%10; |
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} |
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addends[(n2.length-1)-i][j+1]=mult; |
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} |
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if (carryover>0) { |
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addends[(n2.length-1)-i][0]=carryover; |
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} |
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} |
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//printIntDoubleArr(n2.length,n1.length+1,addends);
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struct String sum = {1,"0"}; |
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for (int i=0;i<n2.length;i++) { |
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char val[n1.length+1+i]; |
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for (int j=0;j<n1.length+1+i;j++) { |
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val[j]='0'; |
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} |
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for (int j=0;j<n1.length+1;j++) { |
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val[j]=addends[i][j]+'0'; |
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} |
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sum=add((struct String){n1.length+1+i,val},sum); |
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//printf("\nAA:%s",sum.str);
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} |
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if (sum.str[0]=='0') { |
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char*newStr=malloc(sum.length); |
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for (int i=1;i<sum.length+1;i++) { |
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newStr[i-1]=sum.str[i]; |
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} |
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free(sum.str); |
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sum=(struct String){sum.length-1,newStr}; |
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} |
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//printf("\nA:%s",sum.str);
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return sum; |
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} |
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struct String add(struct String numb1, struct String numb2){ |
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//printf("%s %s\n",numb1.str,numb2.str);
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byte carryover=0; |
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int digitCount=0; |
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char*str = malloc(1); |
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//str[0]='\0';
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if (numb1.length>=numb2.length) { |
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for (int offset=0;offset<numb1.length;offset++) { |
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str = realloc(str,++digitCount); |
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//printf("Digit count is now %d\n",digitCount);
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if (numb2.length>offset) { |
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//printf("%c %c\n",numb1.str[numb1.length-offset-1],numb2.str[numb2.length-offset-1]);
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int sum=((numb1.str[numb1.length-offset-1]-'0')+(numb2.str[numb2.length-offset-1]-'0'))+((carryover>0)?carryover--:0); |
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if (sum>=10) { |
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carryover=1; |
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sum-=10; |
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} |
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str[offset]=sum+'0'; |
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} else { |
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str[offset]=numb1.str[numb1.length-offset-1]+((carryover>0)?carryover--:0); |
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} |
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//str[offset+1]='\0';
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} |
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} else { |
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for (int offset=0;offset<numb2.length;offset++) { |
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str = realloc(str,++digitCount); |
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//printf("Digit count is now %d\n",digitCount);
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if (numb1.length>offset) { |
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//printf("%c %c\n",numb1.str[numb1.length-offset-1],numb2.str[numb2.length-offset-1]);
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int sum=((numb1.str[numb1.length-offset-1]-'0')+(numb2.str[numb2.length-offset-1]-'0'))+((carryover>0)?carryover--:0); |
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if (sum>=10) { |
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carryover=1; |
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sum-=10; |
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} |
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str[offset]=sum+'0'; |
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} else { |
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str[offset]=numb2.str[numb2.length-offset-1]+((carryover>0)?carryover--:0); |
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} |
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//str[offset+1]='\0';
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} |
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} |
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if (carryover>0) { |
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str = realloc(str,++digitCount); |
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str[digitCount-1]='1'; |
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//str[digitCount]='\0';
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} |
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for (int i=0;i<digitCount/2;i++) { |
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char c = str[i]; |
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char c2 = str[digitCount-i-1]; |
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str[digitCount-i-1]=c; |
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str[i]=c2; |
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} |
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str = realloc(str,digitCount+1); |
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str[digitCount]='\0'; |
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struct String newStr = {digitCount,str}; |
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return newStr; |
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} |
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void printLongDoubleArr(int a,int b,long doubleArr[a][b]) { |
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for (int i=0;i<a;i++) { |
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for (int j=0;j<b;j++) { |
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printf("%ld\t",doubleArr[i][j]); |
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} |
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printf("\n"); |
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} |
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} |
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void printIntDoubleArr(int a,int b,int doubleArr[a][b]) { |
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for (int i=0;i<a;i++) { |
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for (int j=0;j<b;j++) { |
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printf("%d\t",doubleArr[i][j]); |
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} |
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printf("\n"); |
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} |
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} |
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struct String createBigNumber(char*numb) { |
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int marker=0; |
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while (numb[marker++]!='\0'); |
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return (struct String){marker-1,numb}; |
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} |
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int*getFactors(int numb) { |
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int*factorList=malloc(sizeof(int)*1); |
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int factorListSize=2; |
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factorList[0]=1; |
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factorList[1]=numb; |
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int max=numb; |
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for (int i=2;i<max;i++) { |
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if (numb%i==0) { |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=i; |
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if (numb/i!=i) { |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=numb/i; |
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max=numb/i; |
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} |
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} |
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} |
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factorList=realloc(factorList,sizeof(int)*++factorListSize); |
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factorList[factorListSize-1]=0; |
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return factorList; |
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} |
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boolean isFactor(int*factorList,int numb) { |
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int counter=0; |
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while (factorList[counter]!=0) { |
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if (numb==factorList[counter]) { |
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return true; |
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} |
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counter++; |
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} |
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return false; |
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} |
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struct String BigPow(int numb1, int numb2) { |
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struct String sum = BigNumber(1); |
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char*newStr = malloc(0); |
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int strLength=0; |
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while (numb1>0) { |
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newStr=realloc(newStr,++strLength); |
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newStr[strLength-1]=(numb1%10)+'0'; |
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numb1/=10; |
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} |
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for (int i=0;i<strLength/2;i++) { |
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char oldC=newStr[strLength-i-1]; |
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newStr[strLength-i-1]=newStr[i]; |
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newStr[i]=oldC; |
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} |
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struct String bigNumb2 = (struct String){strLength,newStr}; |
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for (int i=0;i<numb2;i++) { |
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sum=mult(sum,bigNumb2); |
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} |
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free(newStr); |
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return sum; |
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} |
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boolean equals(struct String str1,struct String str2) { |
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if (str1.length!=str2.length) { |
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return false; |
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} |
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for (int i=0;i<str1.length;i++) { |
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if (str1.str[i]!=str2.str[i]) { |
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return false; |
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} |
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} |
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return true; |
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} |
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#define true 1 |
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#define false 0 |
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#define boolean char |
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#define byte char |
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struct String{ |
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int length; |
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char*str; |
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}; |
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struct String add(struct String numb1, struct String numb2); |
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struct String mult(struct String numb1, struct String numb2); |
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struct String BigPow(int numb1,int numb2); |
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void printLongDoubleArr(int a,int b,long doubleArr[a][b]); |
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void printIntDoubleArr(int a,int b,int doubleArr[a][b]); |
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struct String createBigNumber(char*numb); |
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#define BigNumber(X) createBigNumber(#X) |
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boolean isFactor(int*factorList,int numb); |
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int*getFactors(int numb); |
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boolean equals(struct String str1,struct String str2); |
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#include <stdio.h> |
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#include "utils.h" |
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#include <stdlib.h> |
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#include <math.h> |
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/*
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Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5: |
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Surprisingly there are only three numbers that can be written as the sum of fourth powers of their digits: |
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22=4, 23=8, 24=16, 25=32 |
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32=9, 33=27, 34=81, 35=243 |
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42=16, 43=64, 44=256, 45=1024 |
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52=25, 53=125, 54=625, 55=3125 |
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If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms: |
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1634 = 14 + 64 + 34 + 44 |
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8208 = 84 + 24 + 04 + 84 |
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9474 = 94 + 44 + 74 + 44 |
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4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125 |
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As 1 = 14 is not a sum it is not included. |
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How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100? |
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The sum of these numbers is 1634 + 8208 + 9474 = 19316. |
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https://projecteuler.net/problem=29
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Find the sum of all the numbers that can be written as the sum of fifth powers of their digits. |
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https://projecteuler.net/problem=30
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*/ |
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int main(int argc,char**argv) { |
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struct String*numbs=malloc(sizeof(struct String)*0); |
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long distinctTermCount=0; |
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int arrSize=0; |
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for (int a=2;a<=100;a++) { |
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for (int b=2;b<=100;b++) { |
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struct String newNumb=BigPow(a,b); |
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for (int i=0;i<arrSize;i++) { |
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if (equals(newNumb,numbs[i])) { |
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goto skip; |
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} |
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int counter=0; |
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int currentDigit=10; |
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long digitSum=0; |
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while (counter<10000000) { |
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int tempNumb=currentDigit; |
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digitSum=0; |
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long val=0; |
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while (tempNumb>0) { |
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int digit=tempNumb%10; |
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tempNumb/=10; |
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val=(long)pow(digit,5); |
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digitSum+=val; |
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if (digitSum>currentDigit) { |
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goto next; |
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} |
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numbs=realloc(numbs,sizeof(struct String)*++arrSize); |
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numbs[arrSize-1]=newNumb; |
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//printf("%d^%d: %s\n",a,b,numbs[arrSize-1].str);
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distinctTermCount++; |
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skip: continue; |
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} |
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if (digitSum==currentDigit) { |
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printf("%d has a digit sum that equals its number!\n",currentDigit); |
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} |
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next: |
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currentDigit++; |
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counter++; |
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} |
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printf("\n\nDistinct term count: %ld",distinctTermCount); |
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return 0; |
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} |
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