sigonasr2
/
ProjectEuler
1
0
Fork 0
Code Issues Pull Requests Projects Releases Wiki Activity

Completed 17

Browse Source 
Co-authored-by: sigonasr2 <sigonasr2@gmail.com>
main
sigonasr2, Sig, Sigo 3 years ago committed by GitHub
parent 8e36ea0ab3
commit 046318072f
6 changed files with 389 additions and 3 deletions
Show all changes Ignore whitespace when comparing lines Ignore changes in amount of whitespace Ignore changes in whitespace at EOL
Show Stats Download Patch File Download Diff File
  1. BIN
      archives/17/current
  2. 168
      archives/17/src/main.c
  3. 54
      archives/17/src/utils.c
  4. 9
      archives/17/src/utils.h
  5. BIN
      current
  6. 161
      src/main.c

BIN
archives/17/current
View File

Binary file not shown.

168
archives/17/src/main.c
Unescape View File

@ -0,0 +1,168 @@
#include <stdio.h>
#include "utils.h"
/*
If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance with British usage.
https://projecteuler.net/problem=17
*/
int main(int argc,char**argv) {
int totalCount=0;
int counter=1;
int i=1;
int hundredsDigit=-1;
int tensDigit=-1;
while (i<=1000) {
hundredsDigit=-1;
tensDigit=-1;
counter=i;
int currentCount=totalCount;
if (counter==1000) {
//onethousand (11)
totalCount+=11;
counter-=1000;
printf("onethousand");
}
if (counter>=100) {
hundredsDigit=counter/100;
switch (hundredsDigit) {
case 1:
case 2:
case 6:{
//onehundred (10)
totalCount+=10;
printf("%s",hundredsDigit==1?"one":hundredsDigit==2?"two":"six");
}break;
case 3:
case 7:
case 8:{
//threehundred (12)
totalCount+=12;
printf("%s",hundredsDigit==3?"three":hundredsDigit==7?"seven":"eight");
}break;
case 4:
case 5:
case 9:{
//fourhundred (11)
totalCount+=11;
printf("%s",hundredsDigit==4?"four":hundredsDigit==5?"five":"nine");
}break;
}
printf("hundred");
counter-=hundredsDigit*100;
}
if (counter>=10) {
tensDigit=counter/10;
if (tensDigit!=0) {
if (hundredsDigit!=-1) {
//and (3)
totalCount+=3;
printf("and");
}
if (counter<20) {
switch (counter) {
case 10:{
//ten (3)
totalCount+=3;
printf("ten");
}break;
case 11:{
//eleven (6)
totalCount+=6;
printf("eleven");
}break;
case 12:{
//twelve (5)
totalCount+=5;
printf("twelve");
}break;
case 13:
case 14:
case 19:{
//thirteen (8)
totalCount+=8;
printf("%s",counter==13?"thirteen":counter==14?"fourteen":"nineteen");
}break;
case 15:
case 16:{
//fifteen (7)
totalCount+=7;
printf("%s",counter==15?"fifteen":"sixteen");
}break;
case 17:
case 18:{
//seventeen (9)
totalCount+=9;
printf("%s",counter==17?"seventeen":"eighteen");
}break;
}
counter=0;
} else {
switch (tensDigit) {
case 2:
case 3:
case 8:
case 9:{
//twenty (6)
totalCount+=6;
printf("%s",tensDigit==2?"twenty":tensDigit==3?"thirty":tensDigit==8?"eighty":"ninety");
}break;
case 4:
case 5:
case 6:{
//forty (5)
totalCount+=5;
printf("%s",tensDigit==4?"forty":tensDigit==5?"fifty":"sixty");
}break;
case 7:{
//seventy (7)
totalCount+=7;
printf("seventy");
}break;
}
counter-=tensDigit*10;
}
}
}
if (counter>0) {
if (tensDigit==-1&&hundredsDigit!=-1) {
//and (3)
totalCount+=3;
printf("and");
}
switch (counter) {
case 1:
case 2:
case 6:{
//one (3)
totalCount+=3;
printf("%s",counter==1?"one":counter==2?"two":"six");
}break;
case 3:
case 7:
case 8:{
//three (5)
totalCount+=5;
printf("%s",counter==3?"three":counter==7?"seven":"eight");
}break;
case 4:
case 5:
case 9:{
//four (4)
totalCount+=4;
printf("%s",counter==4?"four":counter==5?"five":"nine");
}break;
}
}
printf(" %d:%d\n",i,totalCount-currentCount);
i++;
}
printf("%d",totalCount);
return 0;
}

54
archives/17/src/utils.c
Unescape View File

@ -0,0 +1,54 @@
#include "utils.h"
#include <stdio.h>
#include <stdlib.h>
struct String add(struct String numb1, struct String numb2){
byte carryover=0;
int digitCount=0;
char*str = malloc(0);
if (numb1.length>=numb2.length) {
for (int offset=0;offset<numb1.length;offset++) {
str = realloc(str,++digitCount);
//printf("Digit count is now %d\n",digitCount);
if (numb2.length>offset) {
//printf("%c %c\n",numb1.str[numb1.length-offset-1],numb2.str[numb2.length-offset-1]);
int sum=((numb1.str[numb1.length-offset-1]-'0')+(numb2.str[numb2.length-offset-1]-'0'))+((carryover>0)?carryover--:0);
if (sum>=10) {
carryover=1;
sum-=10;
}
str[offset]=sum+'0';
} else {
str[offset]=numb1.str[numb1.length-offset-1];
}
}
} else {
for (int offset=0;offset<numb2.length;offset++) {
str = realloc(str,++digitCount);
//printf("Digit count is now %d\n",digitCount);
if (numb1.length>offset) {
//printf("%c %c\n",numb1.str[numb1.length-offset-1],numb2.str[numb2.length-offset-1]);
int sum=((numb1.str[numb1.length-offset-1]-'0')+(numb2.str[numb2.length-offset-1]-'0'))+((carryover>0)?carryover--:0);
if (sum>=10) {
carryover=1;
sum-=10;
}
str[offset]=sum+'0';
} else {
str[offset]=numb2.str[numb2.length-offset-1];
}
}
}
if (carryover>0) {
str = realloc(str,++digitCount);
str[digitCount-1]='1';
}
for (int i=0;i<digitCount/2;i++) {
char c = str[i];
char c2 = str[digitCount-i-1];
str[digitCount-i-1]=c;
str[i]=c2;
}
struct String newStr = {digitCount,str};
return newStr;
}

9
archives/17/src/utils.h
Unescape View File

@ -0,0 +1,9 @@
#define true 1
#define false 0
#define boolean char
#define byte char
struct String{
int length;
char*str;
};
struct String add(struct String numb1, struct String numb2);

BIN
current
View File

Binary file not shown.

161
src/main.c
Unescape View File

@ -2,12 +2,167 @@
#include "utils.h" #include "utils.h"
/* /*
If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
https://projecteuler.net/problem= If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance with British usage.
https://projecteuler.net/problem=17
*/ */
int main(int argc,char**argv) { int main(int argc,char**argv) {
printf("%s",add((struct String){7,"1845920"},(struct String){4,"1829"}).str); int totalCount=0;
int counter=1;
int i=1;
int hundredsDigit=-1;
int tensDigit=-1;
while (i<=1000) {
hundredsDigit=-1;
tensDigit=-1;
counter=i;
int currentCount=totalCount;
if (counter==1000) {
//onethousand (11)
totalCount+=11;
counter-=1000;
printf("onethousand");
}
if (counter>=100) {
hundredsDigit=counter/100;
switch (hundredsDigit) {
case 1:
case 2:
case 6:{
//onehundred (10)
totalCount+=10;
printf("%s",hundredsDigit==1?"one":hundredsDigit==2?"two":"six");
}break;
case 3:
case 7:
case 8:{
//threehundred (12)
totalCount+=12;
printf("%s",hundredsDigit==3?"three":hundredsDigit==7?"seven":"eight");
}break;
case 4:
case 5:
case 9:{
//fourhundred (11)
totalCount+=11;
printf("%s",hundredsDigit==4?"four":hundredsDigit==5?"five":"nine");
}break;
}
printf("hundred");
counter-=hundredsDigit*100;
}
if (counter>=10) {
tensDigit=counter/10;
if (tensDigit!=0) {
if (hundredsDigit!=-1) {
//and (3)
totalCount+=3;
printf("and");
}
if (counter<20) {
switch (counter) {
case 10:{
//ten (3)
totalCount+=3;
printf("ten");
}break;
case 11:{
//eleven (6)
totalCount+=6;
printf("eleven");
}break;
case 12:{
//twelve (5)
totalCount+=5;
printf("twelve");
}break;
case 13:
case 14:
case 19:{
//thirteen (8)
totalCount+=8;
printf("%s",counter==13?"thirteen":counter==14?"fourteen":"nineteen");
}break;
case 15:
case 16:{
//fifteen (7)
totalCount+=7;
printf("%s",counter==15?"fifteen":"sixteen");
}break;
case 17:
case 18:{
//seventeen (9)
totalCount+=9;
printf("%s",counter==17?"seventeen":"eighteen");
}break;
}
counter=0;
} else {
switch (tensDigit) {
case 2:
case 3:
case 8:
case 9:{
//twenty (6)
totalCount+=6;
printf("%s",tensDigit==2?"twenty":tensDigit==3?"thirty":tensDigit==8?"eighty":"ninety");
}break;
case 4:
case 5:
case 6:{
//forty (5)
totalCount+=5;
printf("%s",tensDigit==4?"forty":tensDigit==5?"fifty":"sixty");
}break;
case 7:{
//seventy (7)
totalCount+=7;
printf("seventy");
}break;
}
counter-=tensDigit*10;
}
}
}
if (counter>0) {
if (tensDigit==-1&&hundredsDigit!=-1) {
//and (3)
totalCount+=3;
printf("and");
}
switch (counter) {
case 1:
case 2:
case 6:{
//one (3)
totalCount+=3;
printf("%s",counter==1?"one":counter==2?"two":"six");
}break;
case 3:
case 7:
case 8:{
//three (5)
totalCount+=5;
printf("%s",counter==3?"three":counter==7?"seven":"eight");
}break;
case 4:
case 5:
case 9:{
//four (4)
totalCount+=4;
printf("%s",counter==4?"four":counter==5?"five":"nine");
}break;
}
}
printf(" %d:%d\n",i,totalCount-currentCount);
i++;
}
printf("%d",totalCount);
return 0; return 0;
} }
Write Preview
Loading…
Cancel
Save